Coding Problem 2: Add Two Numbers using linked list [LeetCode - Problem Solving]


You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

 

Example 1:

Input: l1 = [2,4,3], l2 = [5,6,4]
Output: [7,0,8]
Explanation: 342 + 465 = 807.

Example 2:

Input: l1 = [0], l2 = [0]
Output: [0]

Example 3:

Input: l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
Output: [8,9,9,9,0,0,0,1]

 

Constraints:

  • The number of nodes in each linked list is in the range [1, 100].
  • 0 <= Node.val <= 9
  • It is guaranteed that the list represents a number that does not have leading zeros.

Solution : 

package com.coding.problems.leetcode;

class ListNode {
int val;
ListNode next;
ListNode() {}
ListNode(int val) { this.val = val; }
ListNode(int val, ListNode next) { this.val = val; this.next = next; }
}

class Solution {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
ListNode dummyNode = new ListNode(0);
ListNode currentNode = dummyNode;
int carry = 0;
while(l1 != null || l2 != null || carry ==1){
int sum = 0;
if(l1 != null){
sum += l1.val;
l1 = l1.next;
}

if(l2 != null){
sum += l2.val;
l2= l2.next;
}

sum += carry;
carry = sum/10;
currentNode.next = new ListNode(sum%10);;
currentNode = currentNode.next;
}
return dummyNode.next;
}
}

public class AddTwoNumbers {

public static void main(String[] args) {
ListNode l1= new ListNode(2);
ListNode currentNode = l1;
currentNode.next = new ListNode(4);
currentNode = currentNode.next;
currentNode.next = new ListNode(3);

ListNode l2= new ListNode(5);
ListNode currentNodeL2 = l2;
currentNodeL2.next = new ListNode(6);
currentNodeL2 = currentNodeL2.next;
currentNodeL2.next = new ListNode(4);

Solution s = new Solution();
System.out.println(s.addTwoNumbers(l1, l2));
}
}




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